b^2+11b-80=0

Solution for b^2+11b-80=0 equation:

Simplifying
b2 + 11b + -80 = 0

Reorder the terms:
-80 + 11b + b2 = 0

Solving
-80 + 11b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-16 + -1b)(5 + -1b) = 0

Subproblem 1
Set the factor '(-16 + -1b)' equal to zero and attempt to solve:

Simplifying
-16 + -1b = 0

Solving
-16 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -1b = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -1b = 0 + 16
-1b = 0 + 16

Combine like terms: 0 + 16 = 16
-1b = 16

Divide each side by '-1'.
b = -16

Simplifying
b = -16
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {-16, 5}